论坛里又有人问起日期怎样格式化为:2004-08-09 05:02:20这样的格式:于是写了一个左(右)对齐的函数.这函数等价于.NET里String对象的PadLeft和PadRight函数
Function PadLeft(Value,Length,sChar)
Dim strText,I
strText = String(Length,sChar)
strText = strText & Value
LeftPad = Right(strText,Length)
End Function
改一下最下面则为这样:
Function PadRight(Value,Length,sChar)
Dim strText,I
strText = String(Length,sChar)
strText = Value & strText
LeftPad = Left(strText,Length)
End Function
使用例子:日期显示
AA = year(now) & \”-\” & PadLeft(month(now),2,\”0\”) & \”-\” & PadLeft(Day(now),2,\”0\”) & \” \” & PadLeft(Hour(now),2,\”0\”) & \”:\” & PadLeft(Minute(now),2,\”0\”) & \”:\” & PadLeft(Second(now),2,\”0\”)
万能时间补位代码
Public Function ForMatDate(DateAndTime, Para) \’格式化日期(日期时间,格式)
Dim Y, M, D, H, F, S
IF Not ISNumeric(Para) Or Not ISDate(DateAndTime) Then Exit Function
Y = CStr(Year(DateAndTime))
M = CStr(Month(DateAndTime)):IF Len(M) = 1 Then M = \”0\” & M
D = CStr(Day(DateAndTime)):IF Len(D) = 1 Then D = \”0\” & D
H = CStr(Hour(DateAndTime)):IF Len(H) = 1 Then H = \”0\” & H
F = CStr(Minute(DateAndTime)):IF Len(F) = 1 Then F = \”0\” & F
S = CStr(Second(DateAndTime)):IF Len(S) = 1 Then S = \”0\” & S
Select Case Para
Case \”0\”
ForMatDate = Y & \”-\” & M & \”-\” & D & \” \” & H & \”:\” & F & \”:\” & S
Case \”1\”
ForMatDate = Y & \”-\” & M & \”-\” & D & \” \” & H & \”:\” & F
Case \”2\”
ForMatDate = Y & \”-\” & M & \”-\” & D
Case \”3\”
ForMatDate = Y & \”/\” & M & \”/\” & D
Case \”4\”
ForMatDate = Y & \”年\” & M & \”月\” & D & \”日\”
Case \”5\”
ForMatDate = M & \”-\” & D & \” \” & H & \”:\” & F
Case \”6\”
ForMatDate = M & \”/\” & D
Case \”7\”
ForMatDate = M & \”月\” & D & \”日\”
Case \”8\”
ForMatDate = Y & \”年\” & M & \”月\”
Case \”9\”
ForMatDate = Y & \”-\” & M
Case \”10\”
ForMatDate = Y & \”/\” & M
Case \”11\”
ForMatDate = right(Y,2) & \”-\” &M & \”-\” & D & \” \” & H & \”:\” & F
Case \”12\”
ForMatDate = right(Y,2) & \”-\” &M & \”-\” & D
Case \”13\”
ForMatDate = M & \”-\” & D
Case Else
ForMatDate = DateAndTime
End Select
End Function
Response.Write ForMatDate(Now,\”2\”)
asp一段自动补位的函数
function formatsn(getnum,getbit)
dim formatsnnum,formatsnpre,formatsnj
formatsnnum = getbit – len(getnum)
for formatsnj = 1 to formatsnnum
formatsnpre = formatsnpre & \”0\”
next
formatsn = formatsnpre & getnum
end function
使用方法
formatsn(getnum,getbit)
getnum 计数
getbit 共几位
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